A) All of these describe the role of insulin in the body.
B) I only
C) II only
D) III only
E) I and II
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Multiple Choice
A) Yes, because monosaccharides are acidic
B) No, because monosaccharides have too many carbons to be soluble
C) Yes, because monosaccharides can hydrogen bond with water
D) No, because monosaccharides cannot form intermolecular attractive forces with water
E) Yes, because monosaccharides are basic
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Multiple Choice
A) Carbohydrates are used for long term energy storage.
B) Carbohydrates are fuels for cells.
C) Carbohydrates are part of DNA and RNA.
D) Carbohydrates are used in cellular recognition.
E) Carbohydrates make some foods taste sweet.
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Multiple Choice
A) I
B) II
C) III
D) II and III
E) There are equal concentrations of these three species in solution.
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Multiple Choice
A) a
B) b
C) c
D) d
E) e
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Multiple Choice
A) lactose
B) sucrose
C) cellobiose
D) maltose
E) both cellobiose and maltose
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Multiple Choice
A) Both monosaccharides in the disaccharide are linked at their anomeric carbon.
B) Both monosaccharides in the disaccharide are the anomer.
C) No part of the disaccharide can undergo mutarotation.
D) The closed ring form of the sugar linked at its carbon-4 is in equilibrium with its open-chain form.
E) All of these statements are true.
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Multiple Choice
A) Nothing, blood type does not matter in organ transplants.
B) Nothing, Type O is the universal recipient.
C) organ failure
D) coma
E) a mild allergic reaction
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Multiple Choice
A) α-anomer: The -OH on the anomeric carbon is above the ring. β-anomer: The -OH on the anomeric carbon is below the ring.
B) α-anomer: The -CH2OH of carbon 6 is above the ring. β-anomer: The -CH2OH of carbon 6 is below the ring.
C) α-anomer: The -OH on the anomeric carbon is below the ring. β-anomer: The -OH on the anomeric carbon is above the ring.
D) α-anomer: The -CH2OH of carbon 6 is below the ring. β-anomer: The -CH2OH of carbon 6 is above the ring.
E) Both b and d are true.
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Multiple Choice
A) They are identical.
B) They are constitutional isomers.
C) They are diastereomers.
D) They are enantiomers.
E) They are conformers.
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Multiple Choice
A) Cellobiose contains a -(1→4) glycosidic linkage, which is not a substrate for glycosidases in the human stomach.
B) Human enzymes do not accept glucose molecules as substrates.
C) Cellobiose is composed of monosaccharides that are not part of the human diet.
D) The glycosidic bond in this disaccharide is unusually strong.
E) No disaccharide is hydrolyzed by humans.
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Multiple Choice
A) 0
B) 1
C) 2
D) 3
E) 4
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Multiple Choice
A) amylose
B) amylopectin
C) glycogen
D) cellulose
E) amylose and amylopectin
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Multiple Choice
A) I only
B) II and IV only
C) III only
D) I and II only
E) II, III, and IV
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Multiple Choice
A) "-(2→4) "
B) "-(1→4) "
C) "-(1→4) "
D) "-(2→4) "
E) "-(2→6) "
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Multiple Choice
A) pineapple
B) tomatoes
C) potatoes
D) wheat
E) All of these foods contain carbohydrates.
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Multiple Choice
A) a monosaccharide
B) a disaccharide
C) an oligosaccharide
D) a polysaccharide
E) This molecule is not a sugar.
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Multiple Choice
A) amylose
B) amylopectin
C) cellulose
D) glycogen
E) glucose
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Multiple Choice
A) cellulose
B) starch
C) glucose
D) sucrose
E) maltose
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Multiple Choice
A) It is a D-sugar because the hydroxyl at carbon A is to the right.
B) It is a D-sugar because the carbonyl at carbon B is to the right.
C) It is a D-sugar because the hydroxyl at carbon C is to the right
D) It is an L-sugar because the carbonyl at carbon B is to the right.
E) It is an L-sugar because the hydroxyl at carbon C is to the right.
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