Question 1

Evaluate the piecewise function at the given value of the independent variable.
- f(x) ={−x+3 if x<22x−3 if x≥2f ( x )  = \left\{ \begin{array} { l l } - x + 3 & 	ext { if } x < 2 \2 x - 3 & 	ext { if } x \geq 2\end{array} ight.f(x) ={−x+32x−3​ if x<2 if x≥2​

Accepted Answer

A)  
B)  
C)  
D)

Question 2

Determine whether the given function is even, odd, or neither.
- f(x) =−5x5+x3f ( x )  = - 5 x ^ { 5 } + x ^ { 3 }f(x) =−5x5+x3

Accepted Answer

A)   Odd
B)   Neither
C)   Even

Question 3

Give the domain and range of the relation.
-{(6, 7) , (10, -8) , (9, 6) , (9, 2) }

Accepted Answer

A)  domain = {9, 6, 10}; range = {6, 7, -8, 2}
B)  domain = {9, 6, 10, -9}; range = {6, 7, -8, 2}
C)  domain = {9, 6, 10, 19}; range = {6, 7, -8, 2}
D)  domain = {6, 7, -8, 2}; range = {9, 6, 10}

Question 4

Determine whether the relation is a function.
-{(-7, -8) , (-7, -5) , (2, 2) , (4, -8) , (10, 6) }

Accepted Answer

A)  Function
B)  Not a function

Exam 2: Functions and Graphs

Correct Answer
verified

Determine whether the relation is a function. -{(-7, -8) , (-7, -5) , (2, 2) , (4, -8) , (10, 6) }

Correct Answer
verified

Give the domain and range of the relation. -{(6, 7) , (10, -8) , (9, 6) , (9, 2) }

Correct Answer
verified

Determine whether the given function is even, odd, or neither. - $f ( x ) = - 5 x ^ { 5 } + x ^ { 3 }$

Correct Answer
verified

Exam 2: Functions and Graphs

Evaluate the piecewise function at the given value of the independent variable. - f(x) ={−x+3 if x<22x−3 if x≥2f ( x ) = \left\{ \begin{array} { l l } - x + 3 & \text { if } x < 2 \\2 x - 3 & \text { if } x \geq 2\end{array} \right.f(x) ={−x+32x−3​ if x<2 if x≥2​

Correct AnswerverifiedShow Answer

Determine whether the relation is a function. -{(-7, -8) , (-7, -5) , (2, 2) , (4, -8) , (10, 6) }

Correct AnswerverifiedShow Answer

Give the domain and range of the relation. -{(6, 7) , (10, -8) , (9, 6) , (9, 2) }

Correct AnswerverifiedShow Answer

Determine whether the given function is even, odd, or neither. - f(x) =−5x5+x3f ( x ) = - 5 x ^ { 5 } + x ^ { 3 }f(x) =−5x5+x3

Correct AnswerverifiedShow Answer

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Determine whether the given function is even, odd, or neither. - $f ( x ) = - 5 x ^ { 5 } + x ^ { 3 }$

Correct Answer
verified