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Which of the following statements about voltaic and electrolytic cells is correct?


A) The anode will definitely gain weight in a voltaic cell.
B) Oxidation occurs at the cathode of both cells.
C) The free energy change, Δ G, is negative for the voltaic cell.
D) The electrons in the external wire flow from cathode to anode in an electrolytic cell.
E) None of these choices are correct.

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Calculate ΔG° for the reaction of iron(II) ions with one mole of permanganate ions. MnO4(aq) + 8H+(aq) + 5e ⇄ Mn2+(aq) + 4H2O(l) E° = 1.51 V Fe3+(aq) + e ⇄ Fe2+(aq) E°= 0.77 V


A) −71.4 kJ
B) −286 kJ
C) −357 kJ
D) −428 kJ
E) None of these choices are correct.

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A voltaic cell can be prepared from copper and tin. What is the E°cell for the cell that forms from the following half-reactions? Cu2+(aq) + 2e ⇄ Cu(s) E° = 0.34 V Sn4+(aq) + 2e ⇄ Sn2+(aq) E° = 0.13 V


A) 0.47 V
B) 0.21 V
C) -0.21 V
D) -0.47 V
E) 0.42 V

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Consider the reaction in the lead-acid cell Pb(s) + PbO2(s) + 2H2SO4(aq) → 2PbSO4(aq) + 2H2O(l) For which E°cell = 2.04 V at 298 K. ΔG° for this reaction is


A) −3.94 × 10 5 kJ.
B) −3.94 × 10 2 kJ.
C) −1.97 × 10 5 kJ.
D) −7.87 × 10 2 kJ.
E) None of these choices are correct.

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Which, if any, of the following metals would be capable of acting as a sacrificial anode when used with iron pipe? E°Fe = −0.44 V; all E° values refer to the M2+/M half-cell reactions.


A) copper, Cu, E° = 0.15 V
B) cobalt, Co, E° = −0.28 V
C) chromium, Cr, E° = −0.74 V
D) tin, Sn, E° = −0.14 V
E) None of these metals would be capable of acting as a sacrificial anode with iron.

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The value of the equilibrium constant for the reaction of nickel(II) ions with cadmium metal is 1.17 × 105. Calculate ΔG° for the reaction at 25°C.


A) −12.6 kJ
B) −28.9 kJ
C) 12.6 kJ
D) 28.9 kJ
E) None of these choices are correct.

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A concentration cell consists of two Al/Al3+electrodes. The electrolyte in compartment A is 0.050 M Al(NO3) 3 and in compartment B is 1.25 M Al(NO3) 3. What is the voltage of the cell at 25°C?


A) 0.083 V
B) 0.062 V
C) 0.041 V
D) 0.028 V
E) None of these choices are correct.

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In the electrolysis of aqueous sodium sulfate at electrodes of platinum, predict the products of the cell reaction.


A) Sodium and Sulfur
B) Hydrogen and Sulfur
C) Oxygen and Sulfur
D) Oxygen and Sulfuric acid
E) Hydrogen and Oxygen

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E

A voltaic cell prepared using aluminum and nickel has the following cell notation. Al(s) | Al3+(aq) || Ni2+(aq) | Ni(s) Which of the following reactions occurs at the anode?


A) Al( s) → Al 3+( aq) + 3e
B) Al 3+( aq) + 3e → Al( s)
C) Ni( s) → Ni 2+( aq) + 2e
D) Ni 2+( aq) + 2e → Ni( s)
E) None of these choices are correct.

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A voltaic cell is prepared using copper and silver. Its cell notation is shown below. Cu(s) | Cu2+(aq) || Ag+(aq) | Ag(s) Which of the following processes occurs at the cathode?


A) Cu( s) → Cu 2+( aq) + 2e
B) Cu 2+( aq) + 2e → Cu( s)
C) Ag( s) → Ag +( aq) + e
D) Ag +( aq) + e → Ag( s)
E) Cu( s) + 2Ag +( aq) → Cu 2+( aq) + 2Ag( s)

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When the following redox equation is balanced with smallest whole number coefficients, the coefficient for nitrogen dioxide will be __________. I2(s) + HNO3(aq) → HIO3(aq) + NO2(g) + H2O(l)


A) 1
B) 2
C) 4
D) 10
E) None of these choices are correct.

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A voltaic cell is based on the following two half-reactions: Ni+2(aq) + 2e → Ni(s) E° = −0.25 V Cr+3(aq) + 3e- → Cr(s) E° = -0.74 V Sketch the cell and then select the correct statement about it.


A) Cr serves as the cathode.
B) The direction of electron flow through the external wire is from the Ni to the Cr electrode.
C) Anions in solution will migrate toward the Ni +2/Ni electrode.
D) The net cell reaction is 3Ni +2( aq) + 2Cr( s) → 3Ni( s) + 2Cr +3( aq)
E) = 0.99 V

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When the following redox equation is balanced with smallest whole number coefficients, the coefficient for the hydrogen sulfate ion will be Al(s) + HSO4(aq) + OH(aq) → Al2O3(s) + S2(aq) + H2O(l)


A) 1.
B) 3.
C) 4.
D) 8.
E) None of these choices are correct.

Correct Answer

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When the following redox equation is balanced with smallest whole number coefficients, the coefficient for the iodide ion will be I(aq) + NO3(aq) → NO(g) + I2(s) (acidic solution)


A) 2.
B) 3.
C) 6.
D) 8.
E) None of these choices are correct.

Correct Answer

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In the shorthand notation for cells, a double vertical line is used to separate the reduced and oxidized forms of a redox couple.

Correct Answer

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The following half-reactions occur in the mercury battery used in calculators. If E°cell = 1.357 V, calculate the equilibrium constant for the cell reaction at 25°C. (Assume the stoichiometric coefficients in the cell reaction are all equal to 1.) HgO(s) + H2O(l) + 2e ⇄ Hg(l) + 2OH(aq) ZnO(s) + H2O(l) + 2e ⇄ Zn(s) + 2OH(aq)


A) 9.4 × 10 22
B) 7.5 × 10 45
C) 6.4 × 10 63
D) 7.8 × 10 91
E) > 9.9 × 10 99

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What is the value of the equilibrium constant for the cell reaction below at 25°C? E°cell = 0.30 V Sn2+(aq) + Fe(s) ⇄ Sn(s) + Fe2+(aq)


A) 1.2 × 10 5
B) 1.4 × 10 10
C) 8.6 × 10 6
D) 7.1 × 10 11
E) 2.3 × 10 23

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The redox reaction of peroxydisulfate with iodide has been used for many years as part of the iodine clock reaction which introduces students to kinetics. If E°cell = 1.587 V and E° of the cathode half-cell is 0.536 V, what is E° of the anode half-cell? S2O82(aq) + 2H+ + 2I(aq) → 2HSO4(aq) + I2(aq)


A) -1.051 V
B) -2.123 V
C) 1.051 V
D) 2.123 V
E) None of these choices are correct.

Correct Answer

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A

Consider the following balanced redox reaction Mn2+(aq) + S2O82(aq) + 2H2O(l) → MnO2(s) + 4H(aq) + 2SO42(aq) Which of the following statements is true?


A) Mn 2+( aq) is the oxidizing agent and is reduced.
B) Mn 2+( aq) is the oxidizing agent and is oxidized.
C) Mn 2+( aq) is the reducing agent and is oxidized.
D) Mn 2+( aq) is the reducing agent and is reduced.
E) Manganese does not change its oxidation number in this reaction.

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Consider the reaction of iodine with manganese dioxide 3I2(s) + 2MnO2(s) + 8OH-(aq) ⇄ 6I(aq) + 2MnO4(aq) + 4H2O(l) The equilibrium constant for the overall reaction is 8.30 × 107. Calculate E°cell for the reaction at 25°C.


A) −0.36 V
B) −0.18 V
C) −0.12 V
D) −0.060 V
E) None of these choices are correct.

Correct Answer

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D

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