A) I
B) II
C) III
D) IV
E) V
Correct Answer
verified
Essay
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
E) V
Correct Answer
verified
Essay
Correct Answer
verified
Essay
Correct Answer
verified
Essay
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
E) V
Correct Answer
verified
Multiple Choice
A) 1-phenylethanol + manganese dioxide + heat
B) 1-phenylethanol + sodium dichromate + acid + heat
C) tert-butylbenzene + sodium dichromate + acid + heat
D) ethylbenzene + sodium dichromate + acid + heat
E) phenylmethanol + manganese dioxide + heat
Correct Answer
verified
Essay
Correct Answer
verified
Essay
Correct Answer
verified
Multiple Choice
A) tribromobenzene
B) m,m-dibromobromobenzene
C) 3,5-dibromobromobenzene
D) 1,3,5-tribromobenzene
E) m,m,m-tribromobenzene
Correct Answer
verified
Multiple Choice
A) ![]()
B) ![]()
C) ![]()
D) ![]()
E) ![]()
Correct Answer
verified
Multiple Choice
A) ![]()
B) ![]()
C) ![]()
D) ![]()
E) ![]()
Correct Answer
verified
Essay
Correct Answer
verified
View Answer
Multiple Choice
A) a deactivator and a m-director
B) a deactivator and an o,p-director
C) an activator and a m-director
D) an activator and an o,p-director
E) none of the above
Correct Answer
verified
Multiple Choice
A) It protonates the benzene ring in the first step.
B) It protonates the -OH group of the nitric acid.
C) It protonates the nitrogen atom of the nitric acid.
D) It deprotonates the -OH group of the nitric acid.
E) none of the above
Correct Answer
verified
Multiple Choice
A) nitrate; Sn/HCl; NaNO2/HCl,0°C; brominate twice
B) nitrate; Sn/HCl; NaNO2/HCl,0°C; brominate twice; H3PO2
C) nitrate; Sn/HCl; NaNO2/HCl,0°C; H3PO2; brominate twice
D) nitrate; brominate; Sn/HCl; NaNO2/HCl,0°C; CuBr
E) brominate twice
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
E) V
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
E) V
Correct Answer
verified
Multiple Choice
A) It serves as a radical initiator to produce the chlorine radical needed to propagate the chain reaction.
B) It functions by destabilizing the carbocationic intermediate and thereby increases the rate of H+ loss.
C) It serves as a Lewis base catalyst by reacting with Cl2 to generate chloride ions.
D) It functions by destabilizing the benzene through formation of a π-complex.
E) It serves as a Lewis acid catalyst by reacting with the Cl2 and thereby activates it toward attack by benzene's π electrons.
Correct Answer
verified
Showing 61 - 80 of 168
Related Exams