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Shown below are the boxplot and the histogram for the weights (in pounds) of 30 newborn babies in Edmonton,Alberta in May,2014. Shown below are the boxplot and the histogram for the weights (in pounds) of 30 newborn babies in Edmonton,Alberta in May,2014. i) What features of the distribution can you see in both the histogram and the boxplot? ii) What features of the distribution can you see in the histogram that you could not see in the boxplot? A) i) The distribution is bimodal and symmetric.There are two outliers at about 5.4 and 8.6.The mean and median values are about the same. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram. B) i) The distribution is unimodal and skewed to the right.There are no outliers.The mean is greater than the median. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram. C) i) The distribution is unimodal and symmetric.There are two outliers at about 5.4 and 8.6.The mean and median values are about the same. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram. D) i) The distribution is unimodal and skewed to the left.There are no outliers.The mean is less than the median. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram. E) i) The distribution is unimodal and symmetric.There are no outliers.The mean and median values are about the same. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram. i) What features of the distribution can you see in both the histogram and the boxplot? ii) What features of the distribution can you see in the histogram that you could not see in the boxplot?


A) i) The distribution is bimodal and symmetric.There are two outliers at about 5.4 and 8.6.The mean and median values are about the same. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram.
B) i) The distribution is unimodal and skewed to the right.There are no outliers.The mean is greater than the median. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram.
C) i) The distribution is unimodal and symmetric.There are two outliers at about 5.4 and 8.6.The mean and median values are about the same. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram.
D) i) The distribution is unimodal and skewed to the left.There are no outliers.The mean is less than the median. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram.
E) i) The distribution is unimodal and symmetric.There are no outliers.The mean and median values are about the same. ii) The dip at about 7.4 lb,for example,is apparent only from the histogram.

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The back-to-back dotplot shows the number of fatalities per year caused by tornadoes in a certain state for two periods: 1950-1974 and 1975-1999.Explain how you would summarize the centre and spread of each of the variables depicted in the dotplots. The back-to-back dotplot shows the number of fatalities per year caused by tornadoes in a certain state for two periods: 1950-1974 and 1975-1999.Explain how you would summarize the centre and spread of each of the variables depicted in the dotplots. A) The distribution of the number of fatalities per year for the period 1950-1974 is unimodal and approximately symmetric.Therefore,we would be satisfied using the mean to summarize the centre and the standard deviation to summarize spread.For the period 1975-1999,the distribution of the number of fatalities per year is also unimodal,but skewed to the right.Therefore,we would prefer to use a median for centre and an IQR to summarize spread. B) The distribution of the number of fatalities per year for the period 1950-1974 is unimodal,but skewed to the right.Therefore,we would prefer to use a median for centre and an IQR to summarize spread.For the period 1975-1999,the distribution is also unimodal and approximately symmetric.Therefore,we would be satisfied using the mean to summarize the centre and the standard deviation to summarize spread. C) The distribution of the number of fatalities per year for the period 1950-1974 is bimodal.Therefore,we would prefer to use a median to summarize the centre and an IQR to summarize spread.For the period 1975-1999,the distribution of the number of fatalities per year is also bimodal,but skewed to the left.Therefore,we would prefer to use a mean for centre and a standard deviation to summarize spread. D) The distribution of the number of fatalities per year for the period 1950-1974 is unimodal and approximately symmetric.Therefore,we would prefer to use the median to summarize the centre and the standard deviation to summarize spread.For the period 1975-1999,the distribution of the number of fatalities per year is also unimodal,but skewed to the right.Therefore,we would prefer to use the mean for centre and an IQR to summarize spread. E) The distribution of the number of fatalities per year for the period 1950-1974 is unimodal but skewed to the right.Therefore,we would prefer to use a median to summarize the centre and IQR to summarize spread.For the period 1975-1999,the distribution of the number of fatalities per year is also unimodal and skewed to the right.Therefore,we would prefer to use a median for centre and an IQR to summarize spread.


A) The distribution of the number of fatalities per year for the period 1950-1974 is unimodal and approximately symmetric.Therefore,we would be satisfied using the mean to summarize the centre and the standard deviation to summarize spread.For the period 1975-1999,the distribution of the number of fatalities per year is also unimodal,but skewed to the right.Therefore,we would prefer to use a median for centre and an IQR to summarize spread.
B) The distribution of the number of fatalities per year for the period 1950-1974 is unimodal,but skewed to the right.Therefore,we would prefer to use a median for centre and an IQR to summarize spread.For the period 1975-1999,the distribution is also unimodal and approximately symmetric.Therefore,we would be satisfied using the mean to summarize the centre and the standard deviation to summarize spread.
C) The distribution of the number of fatalities per year for the period 1950-1974 is bimodal.Therefore,we would prefer to use a median to summarize the centre and an IQR to summarize spread.For the period 1975-1999,the distribution of the number of fatalities per year is also bimodal,but skewed to the left.Therefore,we would prefer to use a mean for centre and a standard deviation to summarize spread.
D) The distribution of the number of fatalities per year for the period 1950-1974 is unimodal and approximately symmetric.Therefore,we would prefer to use the median to summarize the centre and the standard deviation to summarize spread.For the period 1975-1999,the distribution of the number of fatalities per year is also unimodal,but skewed to the right.Therefore,we would prefer to use the mean for centre and an IQR to summarize spread.
E) The distribution of the number of fatalities per year for the period 1950-1974 is unimodal but skewed to the right.Therefore,we would prefer to use a median to summarize the centre and IQR to summarize spread.For the period 1975-1999,the distribution of the number of fatalities per year is also unimodal and skewed to the right.Therefore,we would prefer to use a median for centre and an IQR to summarize spread.

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Jody got a bank statement each month that listed the balance,in dollars,in her checking account.Here are the balances on several statements. $508.73 $191.48 $535.85 $381.72 $315.88 $485.86 $533.66 $508.12 $515.49 Round your answer to the nearest cent.


A) $497.10
B) $381.72
C) $435.20
D) $441.87
E) $568.11

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Here are some summary statistics for the size of forest fires last year: smallest  fire =72\text { fire } = 72 acres,  mean =493\text { mean } = 493 acres,  median =493\text { median } = 493 acres,  range =7928\text { range } = 7928 acres, IQR=370,\mathrm { IQR } = 370, Q1=197,Q 1 = 197 , standard  deviation =59\text { deviation } = 59 acres.Between what two values are the middle 50% of fire sizes found?


A) 123.25 and 369.75
B) 98.6 and 394.4
C) 197 and 567
D) 72 and 8000
E) 246.5 and 493

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A weight-loss company used the following histogram to show the distribution of the number of pounds lost by clients during the year 2014.Comment on the display. A weight-loss company used the following histogram to show the distribution of the number of pounds lost by clients during the year 2014.Comment on the display.

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Histogram bin widths are too wide to be ...

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Here are some summary statistics for all of the runners in a local 12 kilometre race: slowest  time =124\text { time } = 124 minutes  mean =85\text { mean } = 85 minutes  median =85\text { median } = 85 minutes  range =94\text { range } = 94 minutes IQR=56\mathrm { IQR } = 56 Q1=34\mathrm { Q } 1 = 34 standard  deviation =13\text { deviation } = 13 minutes Is the distribution symmetric,skewed to the left,or skewed to the right? Explain.


A) Skewed to the right; mean higher than median.
B) Symmetric; mean same as median.
C) Skewed to the right; mean lower than median.
D) Skewed to the left; mean higher than median.
E) Skewed to the left; mean lower than median.

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The stem-and-leaf diagram shows the ages of 17 people at a playground in London,Ontario. Age (in years) 7 6 5 4 3 2 1 0 13042323356878466\begin{array} { l } 1 \\3 \\04 \\23 \\233568 \\78 \\\\466\end{array} Key: 3 ∣ 3|~3 = 33 years


A) The distribution of the ages of people at the playground is skewed to the left,with a typical age between 32 and 38.With the exception of the 3 people less than 10 years old,the ages are between 27 and the maximum 71.
B) The distribution of the ages of people at the playground is skewed to the right,with a typical age between 42 and 54.With the exception of the 3 people less than 10 years old,the ages are between 27 and the maximum 71.
C) The distribution of the ages of people at the playground is skewed to the right,with a typical age between 27 and 71.There are 3 outliers,when people are less than 10 years old.
D) The distribution of the ages of people at the playground is skewed to the right,with a typical age between 32 and 38.
E) The distribution of the ages of people at the playground is skewed to the right,with a typical age between 32 and 38.With the exception of the 3 people less than 10 years old,the ages are between 27 and the maximum 71.

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The free throw percentages for the participants in a basketball tournament were compiled.The percents ranged from 33% to 99% with a mean of 56% and a standard deviation of 7%.The quartiles and median percentages were 43%,87%,and 56%.Is the distribution symmetric,skewed to the left,or skewed to the right? Explain.


A) Skewed to the left; mean higher than median.
B) Skewed to the right; mean higher than median.
C) Skewed to the left; mean lower than median.
D) Skewed to the right; mean lower than median.
E) Symmetric; mean same as median.

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The test scores of 19 students are listed below.Find the upper quartile (Q3) by hand. 36 45 49 53 55 56 59 61 62 65 67 71 75 79 82 88 90 92 97


A) 55.5
B) 82.0
C) 65.0
D) 79.0
E) 80.5

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The speed vehicles travelled on a local road was recorded for one month.The speeds ranged from 50 km/h to 65 km/h with a mean speed of 55 km/h and a standard deviation of 7 km/h.The quartiles and median speeds were 53 km/h,62 km/h,and 52 km/h.Is the distribution symmetric,skewed to the left,or skewed to the right? Explain.


A) Skewed to the right; mean lower than median.
B) Skewed to the right; mean higher than median.
C) Skewed to the left; mean higher than median.
D) Skewed to the left; mean lower than median.
E) Symmetric; mean higher than median.

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Heights of a group of male professional athletes,half of whom are gymnasts and half of whom are basketball players.


A) The distribution would likely be unimodal and slightly skewed right.The average height of the gymnasts and basketball players would be about the same.The distribution would be slightly skewed to the right,since it is possible to have some exceptionally tall basketball players.
B) The distribution would likely be uniform,with heights of the professional athletes evenly distributed.
C) The distribution would likely be bimodal and slightly skewed right.The average height of the gymnasts would be at one mode,and the average height of the basketball players would be at the other mode,since basketball players are taller than gymnasts.The distribution would be slightly skewed to the right,since it is possible to have some exceptionally tall basketball players,and it is less likely that the heights of gymnasts would vary significantly.
D) The distribution would likely be bimodal and slightly skewed left.The average height of the gymnasts would be at one mode,and the average height of the basketball players would be at the other mode,since basketball players are taller than gymnasts.The distribution would be slightly skewed to the left,since it is possible to have some exceptionally tall basketball players,and it is less likely that the heights of gymnasts would vary significantly.
E) The distribution would likely be unimodal and symmetric.The average height of the gymnasts and basketball players would be about the same.The distribution would be symmetric,since it is possible to have some exceptionally tall basketball players,and exceptionally short gymnasts.

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Here is the stem-and-leaf display of the midterm test scores for the seventh-period mathematics class.Describe the distribution (shape,centre,spread,unusual features) . Midterm Test Scores 100911800011235566787555889647785394332910\begin{array} { r | l } 10 & 0 \\9 & 11 \\8 & 0001123556678 \\7 & 555889 \\6 & 4778 \\5 & 39 \\4 & \\3 & 3 \\2 & 9 \\1 & \\0 &\end{array} Key: 7 ∣ 5|~5 = 75 points


A) The distribution of the midterm test scores is unimodal and skewed to the left.The median is 80 with an IQR of 17 (Q1 is 68 and Q3 is 85) .The first score is an outlier.
B) The distribution of the midterm test scores is unimodal and skewed to the left.The median is 80 with an IQR of 17 (Q1 is 68 and Q3 is 85) .The first two scores are outliers.
C) The distribution of the midterm test scores is unimodal and skewed to the left.The median is 79 with an IQR of 17 (Q1 is 68 and Q3 is 85) .The first two scores are outliers.
D) The distribution of the midterm test scores is unimodal and skewed to the left.The median is 80 with an IQR of 17 (Q1 is 68 and Q3 is 85) .There are no outliers.
E) The distribution of the midterm test scores is unimodal and skewed to the right.The median is 80 with an IQR of 17 (Q1 is 68 and Q3 is 85) .The first two scores are outliers.

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The weights (in pounds) of 30 newborn babies are listed below. 5.55.75.85.96.16.16.36.46.56.6\begin{array} { l l l l l l l l l l } 5.5 & 5.7 & 5.8 & 5.9 & 6.1 & 6.1 & 6.3 & 6.4 & 6.5 & 6.6 \end{array} 6.76.76.76.97.07.07.07.17.27.2\begin{array} { l l l l l l l l l l } 6.7 & 6.7 & 6.7 & 6.9 & 7.0 & 7.0 & 7.0 & 7.1 & 7.2 & 7.2 \end{array} 7.47.57.77.77.88.08.18.18.38.7\begin{array} { l l l l l l l l l l } 7.4 & 7.5 & 7.7 & 7.7 & 7.8 & 8.0 & 8.1 & 8.1 & 8.3 & 8.7 \end{array} Choose the boxplot that represents the given data. I The weights (in pounds) of 30 newborn babies are listed below. \begin{array} { l l l l l l l l l l } 5.5 & 5.7 & 5.8 & 5.9 & 6.1 & 6.1 & 6.3 & 6.4 & 6.5 & 6.6 \end{array} \begin{array} { l l l l l l l l l l } 6.7 & 6.7 & 6.7 & 6.9 & 7.0 & 7.0 & 7.0 & 7.1 & 7.2 & 7.2 \end{array} \begin{array} { l l l l l l l l l l } 7.4 & 7.5 & 7.7 & 7.7 & 7.8 & 8.0 & 8.1 & 8.1 & 8.3 & 8.7 \end{array} Choose the boxplot that represents the given data. I II III IV V A) I B) II C) III D) IV E) V II The weights (in pounds) of 30 newborn babies are listed below. \begin{array} { l l l l l l l l l l } 5.5 & 5.7 & 5.8 & 5.9 & 6.1 & 6.1 & 6.3 & 6.4 & 6.5 & 6.6 \end{array} \begin{array} { l l l l l l l l l l } 6.7 & 6.7 & 6.7 & 6.9 & 7.0 & 7.0 & 7.0 & 7.1 & 7.2 & 7.2 \end{array} \begin{array} { l l l l l l l l l l } 7.4 & 7.5 & 7.7 & 7.7 & 7.8 & 8.0 & 8.1 & 8.1 & 8.3 & 8.7 \end{array} Choose the boxplot that represents the given data. I II III IV V A) I B) II C) III D) IV E) V III The weights (in pounds) of 30 newborn babies are listed below. \begin{array} { l l l l l l l l l l } 5.5 & 5.7 & 5.8 & 5.9 & 6.1 & 6.1 & 6.3 & 6.4 & 6.5 & 6.6 \end{array} \begin{array} { l l l l l l l l l l } 6.7 & 6.7 & 6.7 & 6.9 & 7.0 & 7.0 & 7.0 & 7.1 & 7.2 & 7.2 \end{array} \begin{array} { l l l l l l l l l l } 7.4 & 7.5 & 7.7 & 7.7 & 7.8 & 8.0 & 8.1 & 8.1 & 8.3 & 8.7 \end{array} Choose the boxplot that represents the given data. I II III IV V A) I B) II C) III D) IV E) V IV The weights (in pounds) of 30 newborn babies are listed below. \begin{array} { l l l l l l l l l l } 5.5 & 5.7 & 5.8 & 5.9 & 6.1 & 6.1 & 6.3 & 6.4 & 6.5 & 6.6 \end{array} \begin{array} { l l l l l l l l l l } 6.7 & 6.7 & 6.7 & 6.9 & 7.0 & 7.0 & 7.0 & 7.1 & 7.2 & 7.2 \end{array} \begin{array} { l l l l l l l l l l } 7.4 & 7.5 & 7.7 & 7.7 & 7.8 & 8.0 & 8.1 & 8.1 & 8.3 & 8.7 \end{array} Choose the boxplot that represents the given data. I II III IV V A) I B) II C) III D) IV E) V V The weights (in pounds) of 30 newborn babies are listed below. \begin{array} { l l l l l l l l l l } 5.5 & 5.7 & 5.8 & 5.9 & 6.1 & 6.1 & 6.3 & 6.4 & 6.5 & 6.6 \end{array} \begin{array} { l l l l l l l l l l } 6.7 & 6.7 & 6.7 & 6.9 & 7.0 & 7.0 & 7.0 & 7.1 & 7.2 & 7.2 \end{array} \begin{array} { l l l l l l l l l l } 7.4 & 7.5 & 7.7 & 7.7 & 7.8 & 8.0 & 8.1 & 8.1 & 8.3 & 8.7 \end{array} Choose the boxplot that represents the given data. I II III IV V A) I B) II C) III D) IV E) V


A) I
B) II
C) III
D) IV
E) V

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The histogram shows the sizes (in acres) of 169 farms in Ontario.In addition to describing the distribution,approximate the percentage of farms that are under 100 acres. The histogram shows the sizes (in acres) of 169 farms in Ontario.In addition to describing the distribution,approximate the percentage of farms that are under 100 acres. A) The distribution of the size of farms in Ontario is skewed to the right.Most of the farms are smaller than 150 acres,with some larger ones,from 150 to 300 acres.Five farms were larger than the rest,over 400 acres.The mode of the distribution is between 0 and 50 acres.It appears that 118 of 169 farms are under 100 acres,approximately 70%. B) The distribution of the size of farms in Ontario is symmetric,with farm sizes ranging from 0 to 450 acres.The mode of the distribution is between 0 and 50 acres.It appears that 118 of 169 farms are under 100 acres,approximately 70%. C) The distribution of the size of farms in Ontario is symmetric,with farm sizes ranging from 0 to 450 acres.The mode of the distribution is between 100 and 150 acres.It appears that 118 of 169 farms are under 100 acres,approximately 70%. D) The distribution of the size of farms in Ontario is skewed to the right.Most of the farms are smaller than 50 acres,with some larger ones,from 150 to 300 acres.Five farms were larger than the rest,over 400 acres.The mode of the distribution is between 0 and 50 acres.It appears that 118 of 169 farms are under 100 acres,approximately 70%. E) The distribution of the size of farms in Ontario is skewed to the right.Most of the farms are smaller than 150 acres,with some larger ones,from 150 to 300 acres.Five farms were larger than the rest,over 400 acres.The mode of the distribution is between 0 and 50 acres.It appears that 62 of 169 farms are under 100 acres,approximately 37%.


A) The distribution of the size of farms in Ontario is skewed to the right.Most of the farms are smaller than 150 acres,with some larger ones,from 150 to 300 acres.Five farms were larger than the rest,over 400 acres.The mode of the distribution is between 0 and 50 acres.It appears that 118 of 169 farms are under 100 acres,approximately 70%.
B) The distribution of the size of farms in Ontario is symmetric,with farm sizes ranging from 0 to 450 acres.The mode of the distribution is between 0 and 50 acres.It appears that 118 of 169 farms are under 100 acres,approximately 70%.
C) The distribution of the size of farms in Ontario is symmetric,with farm sizes ranging from 0 to 450 acres.The mode of the distribution is between 100 and 150 acres.It appears that 118 of 169 farms are under 100 acres,approximately 70%.
D) The distribution of the size of farms in Ontario is skewed to the right.Most of the farms are smaller than 50 acres,with some larger ones,from 150 to 300 acres.Five farms were larger than the rest,over 400 acres.The mode of the distribution is between 0 and 50 acres.It appears that 118 of 169 farms are under 100 acres,approximately 70%.
E) The distribution of the size of farms in Ontario is skewed to the right.Most of the farms are smaller than 150 acres,with some larger ones,from 150 to 300 acres.Five farms were larger than the rest,over 400 acres.The mode of the distribution is between 0 and 50 acres.It appears that 62 of 169 farms are under 100 acres,approximately 37%.

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Shown below are the boxplot,the histogram and summary statistics for the weights (in pounds) of 30 newborn babies: Shown below are the boxplot,the histogram and summary statistics for the weights (in pounds) of 30 newborn babies: \begin{array} { c | c | c | c | c | c | c | c } \text { Count } & \text { Mean } & \text { Median } & \text { StdDev } & \text { Min } & \text { Max } & \text { Q1 } & \text { Q3 } \\ \hline 30 & 6.9 & 7.0 & 0.8 & 5.5 & 8.7 & 6.4 & 7.7 \end{array} Write a few sentences describing the distribution. A) The distribution is unimodal and symmetric.There are no outliers.The mean newborn baby weight was 6.9 \mathrm { lb } with a standard deviation of 0.8 lb. B) The distribution is unimodal and symmetric.There are no outliers.The mean newborn baby weight was 7 \mathrm { lb } with a standard deviation of 1.3 lb. C) The distribution is unimodal and skewed to the right.There are no outliers.The mean newborn baby weight was 7 \mathrm { lb } with an IQR of 1.3 lb. D) The distribution is bimodal and symmetric.There are no outliers.The mean newborn baby weight was 6.9 \mathrm { lb } with a standard deviation of 0.8 lb. E) The distribution is unimodal and skewed to the left.There are no outliers.The mean newborn baby weight was 7 \mathrm { lb } with an IQR of 1.3 lb.  Count  Mean  Median  StdDev  Min  Max  Q1  Q3 306.97.00.85.58.76.47.7\begin{array} { c | c | c | c | c | c | c | c } \text { Count } & \text { Mean } & \text { Median } & \text { StdDev } & \text { Min } & \text { Max } & \text { Q1 } & \text { Q3 } \\\hline 30 & 6.9 & 7.0 & 0.8 & 5.5 & 8.7 & 6.4 & 7.7\end{array} Write a few sentences describing the distribution.


A) The distribution is unimodal and symmetric.There are no outliers.The mean newborn baby weight was 6.9lb6.9 \mathrm { lb } with a standard deviation of 0.8 lb.
B) The distribution is unimodal and symmetric.There are no outliers.The mean newborn baby weight was 7lb7 \mathrm { lb } with a standard deviation of 1.3 lb.
C) The distribution is unimodal and skewed to the right.There are no outliers.The mean newborn baby weight was 7lb7 \mathrm { lb } with an IQR of 1.3 lb.
D) The distribution is bimodal and symmetric.There are no outliers.The mean newborn baby weight was 6.9lb6.9 \mathrm { lb } with a standard deviation of 0.8 lb.
E) The distribution is unimodal and skewed to the left.There are no outliers.The mean newborn baby weight was 7lb7 \mathrm { lb } with an IQR of 1.3 lb.

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The employees at Frank's Furniture earned the following amounts,in dollars,last week. $540.68 $186.11 $264.76 $495.65 $156.26 $533.66 Round your answer to the nearest cent.


A) $423.42
B) $435.42
C) $544.28
D) $ 533.66533.66
E) $362.85

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Here are the number of hours that Bill has exercised each week since he started keeping records. 8.5 6.5 7.1 8.7 6.9 8.5 8.6 7.1 7.8 8.5 8.7 7.9 8.6 6.5 6.5 8.8 6.9 8.6 Round your answer to the nearest tenth.


A) 8.3 hours
B) 9.3 hours
C) 8.0 hours
D) 7.8 hours
E) 7.4 hours

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The students in a math class took the Scholastic Aptitude Test.Their math scores are shown below. 567 630 350 353 503 356 354 552 470 482


A) 461.7
B) 476.0
C) 552.1
D) 452.6
E) 471.1

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A local ice cream shop hand scoops each of its ice cream cones.The cones vary in weight from 120 grams to 216 grams with a mean of 181 grams and a standard deviation of 34 grams.The quartiles and median weights are 146,244,and 202 grams. Is the distribution symmetric,skewed to the left,or skewed to the right? Explain.


A) Skewed to the left; mean higher than median.
B) Skewed to the right; mean higher than median.
C) Symmetric; mean lower than median.
D) Skewed to the right; mean lower than median.
E) Skewed to the left; mean lower than median.

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Last weekend police ticketed 18 men whose mean speed was 72 miles per hour,and 30 women going an average of 64 mph.Overall,what was the mean speed of all the people ticketed?


A) 67 mph
B) 68 mph
C) 69 mph
D) none of those
E) It cannot be determined.

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