Correct Answer
verified
Multiple Choice
A) SELECT title FROM promotion
WHERE retail BETWEEN minretail AND maxretail;
B) SELECT title FROM promotion NATURAL JOIN books
WHERE retail BETWEEN minretail AND maxretail;
C) SELECT title FROM promotion JOIN books
USING retail BETWEEN minretail AND maxretail;
D) none of the above
Correct Answer
verified
Multiple Choice
A) NATURAL JOIN
B) JOIN...ON
C) JOIN...USING
D) all of the above
Correct Answer
verified
Short Answer
Correct Answer
verified
Short Answer
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
Multiple Choice
A) SELECT lastname,firstname,order#
FROM customers NATURAL JOIN orders
WHERE orders.customer# IS NOT NULL;
B) SELECT lastname,firstname,order#
FROM customers,orders
WHERE orders.customer# (+) = customers.customer#;
C) SELECT lastname,firstname,order#
FROM customers,orders
WHERE orders.customer# = customers.customer# (+) ;
D) SELECT lastname,firstname,order#
FROM customers NATURAL JOIN orders
WHERE orders.customer# IS NULL;
Correct Answer
verified
Multiple Choice
A) UNION
B) UNION ALL
C) INTERSECT
D) MINUS
Correct Answer
verified
Multiple Choice
A) 4
B) 3
C) 2
D) 1
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
Short Answer
Correct Answer
verified
Multiple Choice
A) SELECT customer# FROM customers
UNION
SELECT customer# FROM orders;
B) SELECT customer# FROM orders
MINUS
SELECT customer# FROM customers;
C) SELECT customer# FROM orders
INTERSECT
SELECT customer# FROM customers;
D) SELECT customer# FROM customers
MINUS
SELECT customer# FROM orders;
Correct Answer
verified
True/False
Correct Answer
verified
Multiple Choice
A) SELECT lastname,firstname,order#
FROM orders RIGHT OUTER JOIN customers
USING (customer#) ;
B) SELECT lastname,firstname,order#
FROM orders LEFT OUTER JOIN customers
USING (customer#) ;
C) SELECT lastname,firstname,order#
FROM orders FULL OUTER JOIN customers
USING (customer#) ;
D) both a and c
Correct Answer
verified
True/False
Correct Answer
verified
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